x^2+4y^2=20

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Solution for x^2+4y^2=20 equation:


Simplifying
x2 + 4y2 = 20

Solving
x2 + 4y2 = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
x2 + 4y2 + -4y2 = 20 + -4y2

Combine like terms: 4y2 + -4y2 = 0
x2 + 0 = 20 + -4y2
x2 = 20 + -4y2

Simplifying
x2 = 20 + -4y2

Reorder the terms:
-20 + x2 + 4y2 = 20 + -4y2 + -20 + 4y2

Reorder the terms:
-20 + x2 + 4y2 = 20 + -20 + -4y2 + 4y2

Combine like terms: 20 + -20 = 0
-20 + x2 + 4y2 = 0 + -4y2 + 4y2
-20 + x2 + 4y2 = -4y2 + 4y2

Combine like terms: -4y2 + 4y2 = 0
-20 + x2 + 4y2 = 0

The solution to this equation could not be determined.

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